2y^2+9y-486=0

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Solution for 2y^2+9y-486=0 equation:



2y^2+9y-486=0
a = 2; b = 9; c = -486;
Δ = b2-4ac
Δ = 92-4·2·(-486)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-63}{2*2}=\frac{-72}{4} =-18 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+63}{2*2}=\frac{54}{4} =13+1/2 $

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